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x^2+11x+16=9
We move all terms to the left:
x^2+11x+16-(9)=0
We add all the numbers together, and all the variables
x^2+11x+7=0
a = 1; b = 11; c = +7;
Δ = b2-4ac
Δ = 112-4·1·7
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{93}}{2*1}=\frac{-11-\sqrt{93}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{93}}{2*1}=\frac{-11+\sqrt{93}}{2} $
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